Doppler Spread and Coherence Time
Overview
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5.4.3 Doppler Spread and Coherence Time
Delay spread and coherence bandwidth are parameters which describe the time dispersive nature
of the channel in a local area. However, they do not offer information about the time varying
nature of the channel caused by either relative motion between the mobile and base station, or by
movement of objects in the channel. Doppler spread and coherence time are parameters which
describe the time varying nature of the channel in a small-scale region.
Doppler spread BD is a measure of the spectral broadening caused by the time rate of
change of the mobile radio channel and is defined as the range of frequencies over which the
received Doppler spectrum is essentially non-zero. When a pure sinusoidal tone of frequency
fc is transmitted, the received signal spectrum, called the Doppler spectrum, will have components
in the range fc – fd to fc + fd ,where fd is the Doppler shift. The amount of spectral broadening
depends on fd which is a function of the relative velocity of the mobile, and the angle θ
between the direction of motion of the mobile and direction of arrival of the scattered waves. If
the baseband signal bandwidth is much greater than BD the effects of Doppler spread are negligible
at the receiver. This is a slow fading channel.
Coherence time Tc is the time domain dual of Doppler spread and is used to characterize
the time varying nature of the frequency dispersiveness of the channel in the time domain. The
Doppler spread and coherence time are inversely proportional to one another. That is,

Coherence time is actually a statistical measure of the time duration over which the channel
impulse response is essentially invariant, and quantifies the similarity of the channel
response at different times. In other words, coherence time is the time duration over which two
received signals have a strong potential for amplitude correlation. If the reciprocal bandwidth of
the baseband signal is greater than the coherence time of the channel, then the channel will
change during the transmission of the baseband message, thus causing distortion at the receiver.
If the coherence time is defined as the time over which the time correlation function is above 0.5,
then the coherence time is approximately [Ste94]

where fm is the maximum Doppler shift given by fm = v ⁄ λ . In practice, (5.40.a) suggests a
time duration during which a Rayleigh fading signal may fluctuate wildly, and (5.40.b) is often
too restrictive. A popular rule of thumb for modern digital communications is to define the
coherence time as the geometric mean of Equations (5.40.a) and (5.40.b). That is,

The definition of coherence time implies that two signals arriving with a time separation
greater than TC are affected differently by the channel. For example, for a vehicle traveling
60 mph using a 900 MHz carrier, a conservative value TC of can be shown to be 2.22 ms from
Equation (5.40.b). If a digital transmission system is used, then as long as the symbol rate is
greater than 1 ⁄ TC = 454, the channel will not cause distortion due to motion (however,
distortion could result from multipath time delay spread, depending on the channel impulse
response). Using the practical formula of (5.40.c), TC = 6.77 ms and the symbol rate must
exceed 150 bits/s in order to avoid distortion due to frequency dispersion.
Example 5.6
Determine the proper spatial sampling interval required to make smallscale
propagation measurements which assume that consecutive samples
are highly correlated in time. How many samples will be required over 10 m
travel distance if fc = 1900 MHz and v = 50 m/s. How long would it take to
make these measurements, assuming they could be made in real time from
a moving vehicle? What is the Doppler spread BD for the channel?
Solution
For correlation, ensure that the time between samples is equal to TC /2 and
use the smallest value of TC for conservative design.
Using Equation (5.40.b)

Taking time samples at less than half TC, at 282.5 μs corresponds to a
spatial sampling interval of
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Therefore, the number of samples required over a 10 m travel distance is
![]()
The time taken to make this measurement is equal to

The Doppler spread is

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