Owning Class: time
Requires: MathScript RT Module
s = date_to_str(n)
s = date_to_str(n, dateform)
s = date_to_str(s1, dateform)
s = date_to_str(v, dateform)
s = date_to_str(s1, dateform, pivotyear)
Legacy Name: datestr
Converts a time in any supported format to a string. s = date_to_str(s1, dateform) is equivalent to s= date_to_str(s1, dateform, -1).
| Name | Description |
|---|---|
| n | Specifies a time in floating-number format. |
| dateform | Specifies the format for the output string. dateform is a string. |
| s1 | Specifies a time in string format. |
| v | Specifies a time in vector format. |
| pivotyear | Provides additional information about the century if you use the form yy in s1. If you specify a pivotyear, LabVIEW considers s1 to be a time in pivotyear or the 99 years that follow pivotyear. For example, the result of date_to_str('18-Oct-04', 'yyyy/mm/dd', 1900) is equivalent to the result of date_to_str('18-Oct-1904', 'yyyy/mm/dd'). However, if you do not specify pivotyear, or if pivotyear is less than 0, LabVIEW considers s1 to be within a century centered on the current year, or the current year plus or minus 50 years. For example, the result of date_to_str('18-Oct-04', 'yyyy/mm/dd') is equivalent to the result of date_to_str('18-Oct-2004', 'yyyy/mm/dd'). |
| Name | Description |
|---|---|
| s | Returns the time as a string in the dateform format. |
% S = date_to_str(s1, dateform, pivotyear)
S = date_to_str('18-Oct-04', 'yyyy/mm/dd', 1900)
% S = date_to_str(s1, dateform)
S = date_to_str('18-Oct-04', 'yyyy/mm/dd')
% S = date_to_str(v, dateform)
S = date_to_str([2004, 10, 18, 0, 0, 0] , 'yyyy/mm/dd')
% S = date_to_str(n, dateform)
S = date_to_str(2, 'yyyy/mm/dd')